-
Notifications
You must be signed in to change notification settings - Fork 44
Expand file tree
/
Copy pathcommon_parent_in_tree.cpp
More file actions
63 lines (52 loc) · 1.47 KB
/
common_parent_in_tree.cpp
File metadata and controls
63 lines (52 loc) · 1.47 KB
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
/*
* Copyright(c) 2019 Jiau Zhang
* For more information see <https://github.com/JiauZhang/algorithms>
*
* This repo is free software: you can redistribute it and/or modify
* it under the terms of the GNU General Public License as published by
* the Free Software Foundation
*
* It is distributed in the hope that it will be useful,
* but WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
* GNU General Public License for more details.
*
* You should have received a copy of the GNU General Public License
* along with THIS repo. If not, see <http://www.gnu.org/licenses/>.
*/
#include <iostream>
#include <list>
using namespace std;
struct TreeNode {
TreeNode(): left(NULL), right(NULL) {}
struct TreeNode *left;
struct TreeNode *right;
};
//把树公共节点问题转化为链表的公共节点问题
//通过这个函数将树问题转化为从根节点到达给定节点的链表问题
bool GetNodePath(TreeNode *root, TreeNode *node, list<TreeNode *>& path)
{
if (!root)
return false;
if (root == node)
return true;
//遍历root的每个子节点,进行递归查找是否能够到达给定节点
}
TreeNode *GetLastCommonNode(const list<TreeNode *>&path1,
const list<TreeNode *>&path2)
{
/*
a
b
c
/ \
d e
f g
链表是从a开始的,所以只需要同时遍历两个两边,找到最后的
公共节点即可
*/
}
int main(int argc, char **argv)
{
cout << "NOTINSTANCE!" << endl;
}