Avoid rethrows method compilation error

[fummicc1]

As of mockolo 2.1.1, rethrows method is not supported. The following mock produces compile error:

"error: call can throw, but the error is not handled; a function declared 'rethrows' may only throw if its parameter does"

/// @mockable
protocol ThrowableProtocol {
    func foo(action: () throws -> Int) rethrows
}

// ----- mock -----
class ThrowableProtocolMock: ThrowableProtocol {
    init() { }


    private(set) var fooCallCount = 0
    var fooHandler: ((() throws -> Int) throws -> ())?
    func foo(action: () throws -> Int) rethrows {
        fooCallCount += 1
        if let fooHandler = fooHandler {
            try fooHandler(action)
        }
        
    }
}

This is because rethrows only become throwable when parameter of the method has try keyword at the use site.

[sidepelican]

protocol P {
    func f(arg: () throws -> Void) rethrows
}

struct S: P {
    var fHandler: (() throws(any Error) -> Void) throws(any Error) -> Void = { _ in }
    func f<E: Error>(arg: () throws(E) -> Void) throws(E) {
        do {
            try fHandler(arg)
        } catch {
            throw error as! E
        }
    }
}

typed throws can solve this problem

[fummicc1]

@sidepelican

I think Mockolo no longer needs to support rethrows functions because mockolo supports Swift above 5.10 and typed-throws could solve it. Is it correct?

[sidepelican]

Typed-throws is available via swift 6.0
And rethrows still available in swift 6.0.

It is not a priority, but should be considered.

[fummicc1]

I forgot that typed-throws has been implemented in swift 6.0. Thank you so much.