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Force a single link to an array if requested #8
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8e206c3
allow forcing a link to be an array
chadkouse d7682ed
allow forcing a link to be an array
chadkouse c70809d
allow mulpitle links to be passed in at once. cleanup
chadkouse c2745fa
remove cruft
chadkouse 6267fa9
remove unused line
chadkouse cbe88b8
formatting
chadkouse 12194f5
tightening it all up
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
|
|
@@ -148,18 +148,30 @@ | |
| * @see Link | ||
| */ | ||
| Resource.prototype.link = function (link) { | ||
| var forceArray = false; | ||
| var self = this; | ||
| if (arguments.length > 1) { | ||
| link = Link(arguments[0], arguments[1]); | ||
| var href = arguments[1]; | ||
| var rel = arguments[0]; | ||
| if (Array.isArray(href)) { | ||
| forceArray = true; | ||
| href.forEach(function(h) { | ||
| link = Link(rel, h); | ||
| self._links[link.rel] = linkGroupPlus(self._links[link.rel], link, forceArray); | ||
|
Owner
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. I believe you could do |
||
| }); | ||
| return this; | ||
| } | ||
| link = Link(arguments[0], href); | ||
| } | ||
|
|
||
| this._links[link.rel] = linkGroupPlus(this._links[link.rel], link); | ||
| this._links[link.rel] = linkGroupPlus(this._links[link.rel], link, forceArray); | ||
|
|
||
| return this; | ||
| }; | ||
|
|
||
| function linkGroupPlus(group, newLink) { | ||
| function linkGroupPlus(group, newLink, forceArray) { | ||
| if (!group) { | ||
| return newLink; | ||
| return forceArray ? [newLink] : newLink; | ||
| } | ||
| if (Array.isArray(group)) { | ||
| return group.concat(newLink); | ||
|
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||
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Generally, I prefer using
mapandreduceover a plainforEach. I think this might look really nice if you do it.Maybe use one
mapto build a list ofLinks, and make a single call tolinkGroupPlus.